To calculate the residues associated with the singularities of the integrand
function , we can work with the functions
and
separately:
To determine the residues of
Here Note: Riemann would have used different notation, and stated
. This is now more often denoted by
.
We can also write Recall that this is the function with the simple functional equation
and whose only zeros are the
nontrivial zeros of This is an integral function of order 1, meaning that its sequence of zeros {zn} is such that the sum of |zn| -a converges if and only if a > 1 (see Theorem 18, Ingham). We further note that This gives us
Here bo and b1 are constants which
have yet to be determined, and the
Taking logarithms and then deriving gives
Letting s = 0, while observing that Note: The third term in this equation is expressible in terms of the digamma function (confusingly) notated
Therefore we have
for a constant c. This is easily seen to have singularities at s = 1 (residue = -1)
Hence
This leads directly to the explicit formula. To summarise, the steps for
computing the residues are as follows:
back to proof outline archive tutorial mystery new search home contact |