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The generic case.

Suppose that all dimensionless parameters of the medium given by (44) are of the order of 1, and so tex2html_wrap_inline1266 is the only small parameter of the problem. Note that, in particular, tex2html_wrap_inline1446 requires that tex2html_wrap_inline1448 .

One can see that due to smallness of tex2html_wrap_inline1266 when tex2html_wrap_inline1452 , boundary conditions (47) can be satisfied only with small tex2html_wrap_inline1346 and large tex2html_wrap_inline1416 and with the tip tex2html_wrap_inline1398 lying at the I-branch. Then

  eqnarray431

With this precision, curvature distribution tex2html_wrap_inline1414 is the same as that of the involute of a circle. If substituted into equation (41), these asympotics make terms yy'' and tex2html_wrap_inline1466 much less than others, and can be obtained as a solution of this equation with these terms left out. Note that neglecting these very terms corresponds to independence of the normal front velocity on front curvature, which is natural for very small curvature, and consistent with the spiral being an involute of a circle.

If we look for the solution in the form

  eqnarray446

boundary conditions become

  eqnarray452

and so

  eqnarray469

Our solution has a physical sense only at positive tex2html_wrap_inline1416 and tex2html_wrap_inline1308 . Hence, the following inequalities should be fulfilled:

   eqnarray474

Inequality (57) means

  equation479

i.e. spiral wave solution can be found in this way only if the original half-wave solution of the unperturbed system is growing but not shrinking. And (58) shows that the spiral wave solutions are found only to one side of the manifold tex2html_wrap_inline1186 of the parametric space, which in our notations is determined by equation tex2html_wrap_inline1474 .

Finally, the dimensional parameters of the spiral wave are

  eqnarray484



Vadim Biktashev
Sun Apr 13 11:38:06 GMT 1997